Respuestas
Respuesta dada por:
6
Fórmulas:
P x V = n x R x T (Ley de los gases Ideales) (a)
D = m/v (b)
n (moles) = masa/Mm (c)
R = 0.082 (L atm/ mol K)
d = 0.054 g/mL
T = 30 + 273 = 303 K
P = 988 / 760 = 1.3 atm
1. convertir g/mL a g/L
d = 0.054 g x 1000 mL
```````````` ``````````````
1 mL 1 L
d = 54 g/L
2. sustituir en la fórmula (a) los moles
P · V = m · R · T
````
Mm
Mm · P · V = m · R · T
Mm = m · R · T entonces: m/v = d se sustituye
`````````````
V · P
Mm = d ·R · T
``````````
P
Mm = 54 g/L · 0.082 (L atm / mol K ) · 303 K
``````````````````````````````````````````````````````
1.3 atm
Mm = 1032.06 g/mol
P x V = n x R x T (Ley de los gases Ideales) (a)
D = m/v (b)
n (moles) = masa/Mm (c)
R = 0.082 (L atm/ mol K)
d = 0.054 g/mL
T = 30 + 273 = 303 K
P = 988 / 760 = 1.3 atm
1. convertir g/mL a g/L
d = 0.054 g x 1000 mL
```````````` ``````````````
1 mL 1 L
d = 54 g/L
2. sustituir en la fórmula (a) los moles
P · V = m · R · T
````
Mm
Mm · P · V = m · R · T
Mm = m · R · T entonces: m/v = d se sustituye
`````````````
V · P
Mm = d ·R · T
``````````
P
Mm = 54 g/L · 0.082 (L atm / mol K ) · 303 K
``````````````````````````````````````````````````````
1.3 atm
Mm = 1032.06 g/mol
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