Question

Ayuda álgebra!!! ! :'v

Answer 1

P(x-1)= x²-x+2
Q(x+1)= x²+x-2
calcule el valor de:
P(Q(2))
Q(2) = Q(x+1)
2= x+1
1= x
reemplazando en:
Q(x+1) = x²+x-2
Q(1+1) = 1²+1-2
Q(2) = 2-2
Q(2)= 0

P(Q(2)) = P(0)

P(x-1) = P(0)
x-1 = 0
x = 1
reemplazando en:
P(x-1) = x²-x+2
P(1-1) = 1²-1+2
P(0) = 0+2
P(0) = 2
Rpta:
p(Q(2)) = 2