Podrían ayudarme con este problema por favor
Calcula el área y perímetro del polígono formado por los siguientes puntos: A (-2,5), B (-7, -5) y C (6,0). Representa gráficamente el problema.
Respuestas
Respuesta dada por:
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Como son tres puntos A (-2,5), B (-7, -5) y C (6,0) debe ser un triangulo, para hallar su area y perimetro hallemos sus lados(que son distancias)
![d(AB)=\sqrt{ (-5-5)^{2} + (-7-(-2))^{2} } d(AB)=\sqrt{ (-5-5)^{2} + (-7-(-2))^{2} }](https://tex.z-dn.net/?f=+d%28AB%29%3D%5Csqrt%7B+%28-5-5%29%5E%7B2%7D+%2B+%28-7-%28-2%29%29%5E%7B2%7D+%7D+)
![d(AB)=\sqrt{ (-10)^{2} + (-5)^{2} } d(AB)=\sqrt{ (-10)^{2} + (-5)^{2} }](https://tex.z-dn.net/?f=+d%28AB%29%3D%5Csqrt%7B+%28-10%29%5E%7B2%7D+%2B+%28-5%29%5E%7B2%7D+%7D+)
![d(AB)=\sqrt{ 100 + 25 } d(AB)=\sqrt{ 100 + 25 }](https://tex.z-dn.net/?f=+d%28AB%29%3D%5Csqrt%7B+100+%2B+25+%7D+)
![d(AB)=\sqrt{ 125 } d(AB)=\sqrt{ 125 }](https://tex.z-dn.net/?f=+d%28AB%29%3D%5Csqrt%7B+125+%7D+)
![d(AB)=11.1803 d(AB)=11.1803](https://tex.z-dn.net/?f=+d%28AB%29%3D11.1803+)
![d(BC)=\sqrt{ (0-(-5))^{2} + (6-(-7))^{2} } d(BC)=\sqrt{ (0-(-5))^{2} + (6-(-7))^{2} }](https://tex.z-dn.net/?f=+d%28BC%29%3D%5Csqrt%7B+%280-%28-5%29%29%5E%7B2%7D+%2B+%286-%28-7%29%29%5E%7B2%7D+%7D+)
![d(BC)=\sqrt{ (5)^{2} + (13)^{2} } d(BC)=\sqrt{ (5)^{2} + (13)^{2} }](https://tex.z-dn.net/?f=+d%28BC%29%3D%5Csqrt%7B+%285%29%5E%7B2%7D+%2B+%2813%29%5E%7B2%7D+%7D+)
![d(BC)=\sqrt{ 25+ 169 } d(BC)=\sqrt{ 25+ 169 }](https://tex.z-dn.net/?f=+d%28BC%29%3D%5Csqrt%7B+25%2B+169+%7D+)
![d(BC)=\sqrt{ 194 } d(BC)=\sqrt{ 194 }](https://tex.z-dn.net/?f=+d%28BC%29%3D%5Csqrt%7B+194+%7D+)
![d(BC)=13.9283 d(BC)=13.9283](https://tex.z-dn.net/?f=+d%28BC%29%3D13.9283+)
![d(CA)=\sqrt{ (0-5)^{2} + (6-(-2))^{2} } d(CA)=\sqrt{ (0-5)^{2} + (6-(-2))^{2} }](https://tex.z-dn.net/?f=+d%28CA%29%3D%5Csqrt%7B+%280-5%29%5E%7B2%7D+%2B+%286-%28-2%29%29%5E%7B2%7D+%7D+)
![d(CA)=\sqrt{ (-5)^{2} + (8)^{2} } d(CA)=\sqrt{ (-5)^{2} + (8)^{2} }](https://tex.z-dn.net/?f=+d%28CA%29%3D%5Csqrt%7B+%28-5%29%5E%7B2%7D+%2B+%288%29%5E%7B2%7D+%7D+)
![d(CA)=\sqrt{ 25 + 64 } d(CA)=\sqrt{ 25 + 64 }](https://tex.z-dn.net/?f=+d%28CA%29%3D%5Csqrt%7B+25+%2B+64+%7D+)
![d(CA)=\sqrt{ 89 } d(CA)=\sqrt{ 89 }](https://tex.z-dn.net/?f=+d%28CA%29%3D%5Csqrt%7B+89+%7D+)
![d(CA)=9.4339 d(CA)=9.4339](https://tex.z-dn.net/?f=+d%28CA%29%3D9.4339+)
Usaremos la formula de heron , con los lados del triangulo
AB=11.1803, BC=13.9283 , CA)=9.4339 , y p el semiperimetro
perimetro=AB+BC+CA=34.5425
semiperimetro=(AB+BC+CA)/2
semiperimetro=34.5425/2
semiperimetro=17.27125
la formula de heron
![\sqrt{p(p-AB)(p-BC)(p-CA)} \sqrt{p(p-AB)(p-BC)(p-CA)}](https://tex.z-dn.net/?f=+%5Csqrt%7Bp%28p-AB%29%28p-BC%29%28p-CA%29%7D+)
![\sqrt{17.27125(6.09095)(3.34295)(7.83735)} \sqrt{17.27125(6.09095)(3.34295)(7.83735)}](https://tex.z-dn.net/?f=+%5Csqrt%7B17.27125%286.09095%29%283.34295%29%287.83735%29%7D+)
![\sqrt{2756.18222...} \sqrt{2756.18222...}](https://tex.z-dn.net/?f=+%5Csqrt%7B2756.18222...%7D+)
52.49935.... ←esta es el area
Usaremos la formula de heron , con los lados del triangulo
AB=11.1803, BC=13.9283 , CA)=9.4339 , y p el semiperimetro
perimetro=AB+BC+CA=34.5425
semiperimetro=(AB+BC+CA)/2
semiperimetro=34.5425/2
semiperimetro=17.27125
la formula de heron
52.49935.... ←esta es el area
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