Question

EJERCICIOS 93 DEL BALDOR RESUELTOS TODOS?? 

Answer 1

1. x²-y² = (x+y)(x-y)

2. a²-1 = (a+1)(a-1)

3. a²-4 = (a+2)(a-2)

4. 9-b² = (3+b)(3-b)

5. 1-4m² = (1+2m)(1-2m)

6. 16-n² = (4+n)(4-n)

7. a²-25 = (a+5)(a-5)

8. 1-y²= (1+y)(1-y)

9. 4a²-9 = (2a+3)(2a-3)

10. 25-36x⁴ = (5+6x²)(5-6x²)

11. 1-49a²b² = (1+7ab)(1-7ab)

12. 4x²-9 = (2x+3)(2x-3)

13. a²b⁸-c² = (ab⁴+c)(ab⁴-c)

14. 100-x²y⁶ = (10+xy³)(10-xy³)

15. a¹⁰-49b¹² = (a⁵+7b⁶)(a⁵-7b⁶)

16. 25x²y⁴- 121= (5xy²+11)(5xy²-11)

17. 100m²n⁴-169y⁶ = (10mn²+13y³)(10mn²-13y³)

18. a²m⁴n⁶- 144= (am²n³+12)(am²n³-12)

19. 196x²y⁴-225z¹²= (14xy²+15z⁶)(15xy²-15z⁶)

20. 256a¹²-289b⁴m¹⁰=(16a⁶-17b²m⁵)(16a⁶-17b²m⁵)

21. 1-9a²b⁴c⁶d⁸ = (1+3ab²c³d⁴)(1-3ab²c³d⁴)

22. 361x¹⁴-1 =(19x⁷+1)(19x⁷-1)

23. $\frac{1}{4}$-9a² =($\frac{1}{2}$+3a) ($\frac{1}{2}$-3a)

24. 1-$\frac{a^{2} }{25}$= (1+$\frac{a}{5}$)(1-$\frac{a}{5}$)

25. $\frac{1}{16}- \frac{4x^{2} }{49}=( \frac{1}{4}+ \frac{2x}{7})( \frac{1}{4}- \frac{2x}{7})$

26. $\frac{a^{2} }{36}- \frac{x^{6} }{25}= ( \frac{a}{6}+ \frac{x^{3} }{5})( \frac{a}{6}- \frac{ x^{3} }{5})$

27. $\frac{ x^{2} }{100}- \frac{ y^{2} z^{4} }{81}=( \frac{x}{10}+ \frac{yz^{2} }{9})( \frac{x}{10}- \frac{yz ^{2} }{9})$

28. $\frac{x^{6} }{49}- \frac{4a ^{10} }{121}= (\frac{x ^{3} }{7}+ \frac{2a ^{5} }{11} )( \frac{x ^{3} }{7}- \frac{2a ^{5} }{11})$

29. 100m²n⁴ -$\frac{1}{16}x ^{8}= (10mn ^{2} + \frac{1}{4}x ^{4} )(10mn ^{2} - \frac{1}{4} x^{4} )$

30. $a ^{2n}-b ^{2n}= (a ^{n}+b ^{n})(a ^{n}-b ^{n} )$

31. $4x ^{2n}- \frac{1}{9}=(2x ^{n}+ \frac{1}{3})(2 x^{n}- \frac{1}{3} )$

32. $a ^{4n}-225b ^{4} = (a ^{2n}+15b ^{2})(a ^{2n} -15b ^{2})$

33. $16 x^{6m}- \frac{y ^{2n} }{49}=(4 x^{3m}+ \frac{y ^{n} }{7})(4 x^{3m}- \frac{y ^{n} }{7})$

34. $49a ^{10n}- \frac{ b^{12x} }{81}=(7 a^{5}+ \frac{b ^{6x} }{9})(7a ^{5}- \frac{b ^{6x} }{9})$

35. $a ^{2n}b ^{4n}- \frac{1}{25}= ( a ^{n}b ^{2n}+ \frac{1}{5} )(a ^{n}b ^{2n}- \frac{1}{5} )$

36. $\frac{1}{100}- x^{2n} = (\frac{1}{10}+x ^{n} )( \frac{1}{10}- x^{n})$