Question

 ayudemen xfa    3x-4y=41
                          11x+6y=47

Answer 1

$\left \{ {{3x-4y=41} \atop {11x+6y=47}} \right. \\ \\3x-4y=41 \\ 3x=41+4y \\ \\ x= \frac{41+4y}{3} \\ \\ 11x+6y=47 \\ 11x=47-6y \\ \\ x= \frac{47-6y}{11}$

$x=x \\ \\ \frac{41+4y}{3}= \frac{47-6y}{11} \\ \\ 11(41+4y)=3(47-6y) \\ \\ 451+44y=141-18y \\ \\ 44y-18y=141-451 \\ \\ 26y=-310 \\ \\ y= -\frac{310}{26} \\ \\ \boxed{y=-\frac{155}{13} }$

$x= \frac{41+4y}{3} \\ \\ x= \frac{41-4 \frac{155}{13} }{3} \\ \\ x= \frac{ \frac{533}{13} - \frac{620}{13} }{3} \\ \\ x= \frac{ -\frac{87}{13} }{3} \\ \\ x=-\frac{87}{39}\\ \\\boxed{ x= -\frac{29}{13}}$