Hola alguien que me ayude a calcular la moralidad de estás soluciones!!!
A) 18g. de HNO3 en 50 ml de solución.
B) 46g. de CoCl3 en 500 ml de solución.
C) 9g. de HgF2 en 1000ml de solución.
D) 73g. de AL(OH)3 en 725ml de solución.
E) 23g. de RA3 N2 en 400 ml de solución.
Respuestas
Respuesta dada por:
1
A) Mm HNO3 = 63 g/mol
1. convertir mL a L
L = 50 / 1000 = 0.05 litros
2. calcular moles
moles = 18 g HNO3 x 1 mol HNO3
``````````````````
63 g HNO3
moles = 0.285
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.285 mol / 0.05 L
M = 5.7 molar
B) Mm CoCl3 = 165.3 g/mol
1. convertir mL a L
L = 500 / 1000 = 0.5 litros
2. calcular moles
moles = 46 g CoCl3 x 1 mol CoCl3
``````````````````
165.3 g CoCl3
moles = 0.278
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.278 mol / 0.5 L
M = 0.556 molar
C) Mm HgF2 = 238.58 g/mol
1. convertir mL a L
L = 1000 / 1000 = 1 litros
2. calcular moles
moles = 9 g HgF2 x 1 mol HgF2
``````````````````
238.58 g HgF2
moles = 0.037
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.07 mol / 1 L
M = 0.07 molar
D) Mm Al(OH)3 = 78 g/mol
1. convertir mL a L
L = 725 / 1000 = 0.725 litros
2. calcular moles
moles =73 g Al(OH)3 x 1 mol Al(OH)3
``````````````````
78 g Al(OH)3
moles = 0.94
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.94 mol / 0.725 L
M = 1.29 molar
E) Mm Ra3N2 = 706 g/mol
1. convertir mL a L
L = 400 / 1000 = 0.4 litros
2. calcular moles
moles = 23 g Ra3N2 x 1 mol Ra3N2
``````````````````
706 g Ra3N2
moles = 0.033
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.033 mol / 0.4 L
M = 0.083 molar
1. convertir mL a L
L = 50 / 1000 = 0.05 litros
2. calcular moles
moles = 18 g HNO3 x 1 mol HNO3
``````````````````
63 g HNO3
moles = 0.285
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.285 mol / 0.05 L
M = 5.7 molar
B) Mm CoCl3 = 165.3 g/mol
1. convertir mL a L
L = 500 / 1000 = 0.5 litros
2. calcular moles
moles = 46 g CoCl3 x 1 mol CoCl3
``````````````````
165.3 g CoCl3
moles = 0.278
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.278 mol / 0.5 L
M = 0.556 molar
C) Mm HgF2 = 238.58 g/mol
1. convertir mL a L
L = 1000 / 1000 = 1 litros
2. calcular moles
moles = 9 g HgF2 x 1 mol HgF2
``````````````````
238.58 g HgF2
moles = 0.037
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.07 mol / 1 L
M = 0.07 molar
D) Mm Al(OH)3 = 78 g/mol
1. convertir mL a L
L = 725 / 1000 = 0.725 litros
2. calcular moles
moles =73 g Al(OH)3 x 1 mol Al(OH)3
``````````````````
78 g Al(OH)3
moles = 0.94
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.94 mol / 0.725 L
M = 1.29 molar
E) Mm Ra3N2 = 706 g/mol
1. convertir mL a L
L = 400 / 1000 = 0.4 litros
2. calcular moles
moles = 23 g Ra3N2 x 1 mol Ra3N2
``````````````````
706 g Ra3N2
moles = 0.033
3. calcular la MOLARIDAD aplicando la fórmula:
M = moles soluto / V(L)
M = 0.033 mol / 0.4 L
M = 0.083 molar
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