Question

Hola alguien que me ayude a calcular la moralidad de estás soluciones!!!

A) 18g. de HNO3 en 50 ml de solución.

B) 46g. de CoCl3 en 500 ml de solución.

C) 9g. de HgF2 en 1000ml de solución.

D) 73g. de AL(OH)3 en 725ml de solución.

E) 23g. de RA3 N2 en 400 ml de solución.

Answer 1

A) Mm HNO3 = 63 g/mol

1. convertir mL a L

L = 50 / 1000 = 0.05 litros

2. calcular moles

moles = 18 g HNO3   x  1 mol HNO3
                                      ``````````````````
                                       63 g HNO3

moles = 0.285

3. calcular la MOLARIDAD aplicando la fórmula:

M = moles soluto / V(L)

M = 0.285 mol / 0.05 L

M = 5.7 molar

B)    Mm CoCl3 = 165.3 g/mol

1. convertir mL a L

L = 500 / 1000 = 0.5 litros

2. calcular moles

moles = 46 g CoCl3   x  1 mol CoCl3
                                      ``````````````````
                                      165.3 g CoCl3

moles = 0.278

3. calcular la MOLARIDAD aplicando la fórmula:

M = moles soluto / V(L)

M = 0.278 mol / 0.5 L

M = 0.556 molar

C)  Mm HgF2 = 238.58 g/mol

1. convertir mL a L

L = 1000 / 1000 = 1 litros

2. calcular moles

moles =   9 g HgF2   x    1 mol HgF2
                                      ``````````````````
                                      238.58 g HgF2

moles = 0.037

3. calcular la MOLARIDAD aplicando la fórmula:

M = moles soluto / V(L)

M = 0.07 mol / 1 L

M = 0.07 molar

D)  Mm Al(OH)3 = 78 g/mol

1. convertir mL a L

L = 725 / 1000 = 0.725 litros

2. calcular moles

moles =73 g Al(OH)3   x  1 mol Al(OH)3
                                      ``````````````````
                                       78 g Al(OH)3

moles = 0.94

3. calcular la MOLARIDAD aplicando la fórmula:

M = moles soluto / V(L)

M = 0.94 mol / 0.725 L

M = 1.29 molar

E)    Mm Ra3N2 = 706 g/mol

1. convertir mL a L

L = 400 / 1000 = 0.4 litros

2. calcular moles

moles = 23 g Ra3N2  x  1 mol Ra3N2
                                      ``````````````````
                                         706 g Ra3N2
moles = 0.033

3. calcular la MOLARIDAD aplicando la fórmula:

M = moles soluto / V(L)

M = 0.033 mol / 0.4 L

M = 0.083 molar