Sen x / 1+ cos x + 1+ cos x / sen x = 2 csc x

Respuestas

Respuesta dada por: Wellington1308
95
{\dfrac{\sin x}{1+\cos x}+\dfrac{1+\cos x}{\sin x}=}\\\\\\{\dfrac{\sin^2x+(1+\cos x)^2}{\sin x(1+\cos x)}=}\\\\\\{\dfrac{\sin^2x+1+2\cos x+\cos^2x}{\sin x(1+\cos x)}=\ \ \ \ \ \ recordemos:\ \sin^2x +\cos^2x=1}\\\\\\{\dfrac{1+1+2\cos x}{\sin x(1+\cos x)}=}\\\\\\{\dfrac{2+2\cos x}{\sin x(1+\cos x)}=}\\\\\\{\dfrac{2(1+\cos x)}{\sin x(1+\cos x)}=}\\\\\\{\dfrac{2}{\sin x}=}\\\\\\{\boxed{2\csc x}}
Respuesta dada por: og984676
3

Respuesta:

eso esta mal 1 - cos x no es 2cosx

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