Question

Como se resuelve esta ecuación 2x²+10x-48=0

Answer 1

Resolvemos usando la formula general:

$\boxed{x= \dfrac{-b \pm \sqrt{b ^{2}-4ac } }{2a} }$

$\underline{\textbf{Datos}}: \\ \\ a= 2 \\ b= 10 \\ c= -48$

Sustituimos los datos:

$x= \dfrac{-10 \pm \sqrt{10 ^{2}-4(2)(-48) } }{2(2)} \\ \\ \\ x= \dfrac{-10 \pm \sqrt{100+384 } }{4} \\ \\ \\ x= \dfrac{-10 \pm \sqrt{484 } }{4} \\ \\ \\ x= \dfrac{-10 \pm 22 }{4} \\ \\ \\ \checkmark x_{1} = \dfrac{-10+ 22 }{4} \\ \\ \\ x_{1} = \dfrac{12 }{4} \\ \\ \boxed{\boxed{\textbf{x}_{\textbf{1}} \textbf{= 3}}} \checkmark\checkmark \\ \\ \\ \checkmark x_{1} = \dfrac{-10-22 }{4} \\ \\ \\ x_{1} = \dfrac{-32 }{4}$

$\boxed{\boxed{\textbf{x}_{\textbf{2}} \textbf{= -8}}} \checkmark\checkmark$

Saludos y Suerte!!!!!!!!!!!!!!!!!!!!!!!!!!!!!