Question

pregunta 1; 3x3 + 4x2 + 12x + 16 = 0

pregunta 2; x^3+x^2-6x=0

pregunta 3; x^3+3x^2-6x-18=0

Buen dia.
Me pudieran ayudar con estos ejercicios

Answer 1

Sin respuesta al pedido de aclaración
Supongo que se trata de resolver las ecuaciones
Vamos a hacerlo por factorización
Todas son ecuaciones de trecer grado. Tienen 3 raices

En la secuencia que aparen

                 (3x + 4(x^2 + 4) = 0

Cada factor será nulo
                  3x + 4 = 0
                        3x = - 4
                          x = - 4/3
                                                    x1 = - 4/3
                 x^2 + 4 = 0
                       x^2 = - 4
                          x = √-4
                            = +/- 2i
                                                    x2 = - 2i
                                                    x3 = 2i
                                                                 S = {-2i, 2i, - 4/3}

Igual anterior
            x(x + 3)(x - 2) = 0
                                             x1 = 0
                    x + 3 = 0
                                             x2 = - 3
                   x - 2 = 0
                                             x3 = 2
                                                               S = {-3, 0, 2}

Igual
          (x + 3)(x^2 - 6 = 0
                       x + 3 = 0
                                               x1 = - 2
                    x^2 - 6 = 0
                         x^2 = 6
                         x = +/- √6
                                                x2 = - √6
                                                x3 = √6
                                                                    S = {- √6, - 2, √6}