Respuestas
Respuesta dada por:
1
3.
a MnO2 + b HCl → c MnCl2 + d O2 + e H2O
asignar un número a cualquier variable literal a = 2
Mn: a = c
Cl: b = 2c
H: b = 2e
O: 2a = 2d + 1e
resolver cada ecuación:
a = 2
2 = c ⇒ c = 2
b = 2(2) ⇒ b = 4
b = 2e ⇒ 4 = 2e donde e = 4/2 = 2
2a = 2d + 1e
2(2) = 2d + 2
4 - 2 = 2d ⇒ d = 2/2 = 1
a =2 b = 4 c = 2 d = 1 e = 2
balancear la ecuacion:
a MnO2 + b HCl → c MnCl2 + d O2 + e H2O
2 MnO2 + 4 HCl → 2 MnCl2 + O2 + 2 H2O
4. aHCl + bKClO3 → c KCl + d H2O + e Cl2
asignar b = 1
Cl: a + b = c + 2e
K: b = c
H: a = 2d
O: 3b = 1d
remplazar en las ecuaciones
a = 6
b = 1
c = 1
d = 3
e = 3
3b = 1d ⇒ 3(1) = 1d ⇒ d = 3
a = 2d ⇒ a = 2(3) ⇒ a = 6
a + b = c + 2e
6 + 1 = 1 + 2e ⇒ 7 - 1 = 2e ⇒ e = 6/2 = 3
balancear.
6HCl + KClO3 → KCl + 3 H2O + 3 Cl2
5. a HNO2 + b H2S → c S + d NO + e H2O
asignar a = 2
N: a = d
S: b = c
H: a + 2b = 2e
O: 3a = 1d + 1e
a = d ⇒ d = 2
3a = 1d + 1e ⇒ 3(2) = 2(1) + 1e
6 = 2 + 1e ⇒ e = 4
a + 2b = 2e
2 + 2b = 8 ⇒ 2b = 6 ⇒ b = 6/2 = 3
a = 2
b = 3
c = 3
d = 2
e = 4
balancear.
2HNO2 + 3H2S → 3 S + 2 NO + 4 H2O
6. ₊₂ ₋₂ ₀ ₀ ₊₄ ₋₂
FeO + C → Fe + CO2
2e⁻ + 4H⁺ + FeO → Fe + 2H2O 4=2 intercambiar e⁻
2H2O + C → CO2 + 4H⁺ + 4e⁻ 2 = 1 simplicar
````````````````````````````````````````````````````````````````````````````````````````````
4H⁺ + 2FeO + 4H2O + C → 2Fe + 4H2O + CO2 + 4H⁺ simplificar 4H⁺
2FeO + C → 2 Fe + CO2 BALANCEADA
a MnO2 + b HCl → c MnCl2 + d O2 + e H2O
asignar un número a cualquier variable literal a = 2
Mn: a = c
Cl: b = 2c
H: b = 2e
O: 2a = 2d + 1e
resolver cada ecuación:
a = 2
2 = c ⇒ c = 2
b = 2(2) ⇒ b = 4
b = 2e ⇒ 4 = 2e donde e = 4/2 = 2
2a = 2d + 1e
2(2) = 2d + 2
4 - 2 = 2d ⇒ d = 2/2 = 1
a =2 b = 4 c = 2 d = 1 e = 2
balancear la ecuacion:
a MnO2 + b HCl → c MnCl2 + d O2 + e H2O
2 MnO2 + 4 HCl → 2 MnCl2 + O2 + 2 H2O
4. aHCl + bKClO3 → c KCl + d H2O + e Cl2
asignar b = 1
Cl: a + b = c + 2e
K: b = c
H: a = 2d
O: 3b = 1d
remplazar en las ecuaciones
a = 6
b = 1
c = 1
d = 3
e = 3
3b = 1d ⇒ 3(1) = 1d ⇒ d = 3
a = 2d ⇒ a = 2(3) ⇒ a = 6
a + b = c + 2e
6 + 1 = 1 + 2e ⇒ 7 - 1 = 2e ⇒ e = 6/2 = 3
balancear.
6HCl + KClO3 → KCl + 3 H2O + 3 Cl2
5. a HNO2 + b H2S → c S + d NO + e H2O
asignar a = 2
N: a = d
S: b = c
H: a + 2b = 2e
O: 3a = 1d + 1e
a = d ⇒ d = 2
3a = 1d + 1e ⇒ 3(2) = 2(1) + 1e
6 = 2 + 1e ⇒ e = 4
a + 2b = 2e
2 + 2b = 8 ⇒ 2b = 6 ⇒ b = 6/2 = 3
a = 2
b = 3
c = 3
d = 2
e = 4
balancear.
2HNO2 + 3H2S → 3 S + 2 NO + 4 H2O
6. ₊₂ ₋₂ ₀ ₀ ₊₄ ₋₂
FeO + C → Fe + CO2
2e⁻ + 4H⁺ + FeO → Fe + 2H2O 4=2 intercambiar e⁻
2H2O + C → CO2 + 4H⁺ + 4e⁻ 2 = 1 simplicar
````````````````````````````````````````````````````````````````````````````````````````````
4H⁺ + 2FeO + 4H2O + C → 2Fe + 4H2O + CO2 + 4H⁺ simplificar 4H⁺
2FeO + C → 2 Fe + CO2 BALANCEADA
Preguntas similares
hace 6 años
hace 6 años
hace 9 años
hace 9 años