Question

como calcular logx=log6+3log5-1/2log9

Answer 1

logx = log6 + 3log5 - (1/2)log9

logx = log6 + log(5^3) - log(9^(1/2))

logx = log6 + log(125) - log3

logx = log (6*125) - log 3

logx = log (750) - log3

logx = log(750/3)

logx = log250

x = 250