Question

tgx + cotgx = secx * cosec

FUNCIONES TRIGONOMETRICAS

Answer 1

$tan \alpha +cot \alpha =sec \alpha .csc \alpha \\ \\ \frac{sen \alpha }{cos \alpha }+ \frac{cos \alpha }{sen \alpha } =sec \alpha .csc \alpha \\ \\ \frac{sen^{2} \alpha +cos^{2} \alpha }{cos \alpha .sen \alpha } =sec \alpha .csc \alpha \\ \\ \frac{1}{cos \alpha .sen \alpha }=sec \alpha.csc \alpha \\ \\ \frac{1}{cos \alpha }. \frac{1}{sen \alpha }=sec \alpha .csc \alpha \\ \\ sec \alpha .csc \alpha =sec \alpha .csc \alpha$