Respuestas
Respuesta dada por:
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Ley de los Gases Ideales
V · P = n · R · T
m = 125.5 g
Mm N2O = 44 g/mol
V = ?
P = 95 atm
T = 13 ºC + 273 = 286 K
R = 0.0821 (L atm / mol K)
1. calcular moles aplicando la fórmula n = masa/Mm
n = 125.5 g
````````````
44 g/mol
n = 2.852 moles
2. calcular volumen
V = 2.852 mol · 0.0821 (L atm/mol K) · 286 K
``````````````````````````````````````````````````````````
95 atm
V = 0.705 L
mL = 0.705 x 1000 = 705 mL
V · P = n · R · T
m = 125.5 g
Mm N2O = 44 g/mol
V = ?
P = 95 atm
T = 13 ºC + 273 = 286 K
R = 0.0821 (L atm / mol K)
1. calcular moles aplicando la fórmula n = masa/Mm
n = 125.5 g
````````````
44 g/mol
n = 2.852 moles
2. calcular volumen
V = 2.852 mol · 0.0821 (L atm/mol K) · 286 K
``````````````````````````````````````````````````````````
95 atm
V = 0.705 L
mL = 0.705 x 1000 = 705 mL
gloricas:
muchas gracias, te lo agradezco
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