Question

Calcula la molaridad de 300 mL de una disolución acuosa que contiene 12 g de ácido sulfúrico

Answer 1

Mm H2SO4 = 98 g/mol

1. convertir mL a L

L = 300 / 1000 = 0.300 litros

2. calcular moles de soluto

n = masa/Mm

n =   12 g
     `````````````
      98 g/mol

n = 0.122 moles

3. Calcular la M = moles soluto /V(L)

M = 0.122 mol
      ````````````````
         0.300 L

M = 0.40 molar