Question

na2cr2o7+h2o+s---so2+naoh+cr2o3 ayudemen a balanciarla

Answer 1

Oxidacion
S = 0 ____4

Reduccion
Cr = 6____3

S+0 ________ 4e________S+4
Cr2+6_______ 6e________Cr2+3


S ___________2e________S.......|||×3
Cr2 _________ 3e________Cr2.....|||×2
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3S __________6e________3S
2Cr2_________6e________2Cr2
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3S + 2Cr2. = 3S + 2Cr2


2 Na2Cr2O7 + 2 H2O + 3 S = 3 SO2 + 4 NaOH + 2 Cr2O3