Question

resuelve las siguientes ecuaciones cuadraticas por factorizacion

x2-25x+156=0

x2-25+136=0

x2-25+46=0

x2-25+100=0

Answer 1

\begin{array}{lcl}{{x}^{2}-25x+156=0}\\{{x}^{2}-25+136=0}\\{{x}^{2}-25+46=0}\\{{x}^{2}-25+100=0}\end{array}
​x
​2
​​ −25x+156=0
​x
​2
​​ −25+136=0
​x
​2
​​ −25+46=0
​x
​2
​​ −25+100=0
​​
1 Solve for xx in {x}^{2}-25x+156=0x
​2
​​ −25x+156=0How?
x=13,12x=13,12

2 Substitute x=13,12x=13,12 into {x}^{2}-25+136=0x
​2
​​ −25+136=0How?
111+{(13,12)}^{2}=0111+(13,12)
​2
​​ =0

3 Since 111+{(13,12)}^{2}=0111+(13,12)
​2
​​ =0 is not true, this is an inconsistent system
No Solution

Answer 2

Respuesta:

x2-25x+156=0

Explicación paso a paso:

156+25=181

x2-181=0

x2=181-0

x2=181

x=√181=13,45362405