Respuestas
Respuesta dada por:
75
Mm H2SO4 = 98 g/mol
1. convertir mL a L
L = 200 / 1000 = 0.2 Litros
2. calcular moles despejando de la fórmula M = n/V(L)
n = 1.8 mol/ L x 0.2 L = 0.36 moles
3.. calcular masa aplicando la fórmula n = masa/Mm
masa = 0.36 mol x 98 g/mol
masa = 35.28 g
4. calcular Peq = Mm/ Nº H⁺
Peq. = 98 g/mol
````````````
2
Peq. = 49 g/eq
5. calcular equivalentes:
eqv. = masa/Peq.
eqv. = 35.28 g/ 49 g/eq
eq. = 0.72
6. calcular N = eq. / V(L)
N = 0.72 eq. / 0.2 L
N = 3.6 normal
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2da. forma directa.
M = N
``
2
entonces: N = 2M
sustituir: N = 2(1.8) = 3.6 Normal
1. convertir mL a L
L = 200 / 1000 = 0.2 Litros
2. calcular moles despejando de la fórmula M = n/V(L)
n = 1.8 mol/ L x 0.2 L = 0.36 moles
3.. calcular masa aplicando la fórmula n = masa/Mm
masa = 0.36 mol x 98 g/mol
masa = 35.28 g
4. calcular Peq = Mm/ Nº H⁺
Peq. = 98 g/mol
````````````
2
Peq. = 49 g/eq
5. calcular equivalentes:
eqv. = masa/Peq.
eqv. = 35.28 g/ 49 g/eq
eq. = 0.72
6. calcular N = eq. / V(L)
N = 0.72 eq. / 0.2 L
N = 3.6 normal
``````````````````````````````````````````````````````````````````````
2da. forma directa.
M = N
``
2
entonces: N = 2M
sustituir: N = 2(1.8) = 3.6 Normal
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