Question

resuelve las siguientes adiciones y sustracciones de fracciones
a. 3/5 + 2/5 =
b. 1/7 + 2/3 =
c. 7 1/2 + 1/2
d.6/7 - 3/7
e. 231/15 - 651/3 =
f. 756 3/4 - 245 1/2 =

Porfa diganme el procedimiento

Answer 1

$1) \frac{3}{5} + \frac{2}{5} = \frac{3+2}{5} = \frac{5}{5} = \frac{1}{1} = 1$

$2) \frac{1}{7} + \frac{2}{3} = \frac{21:7.1+21:3.2}{21} = \frac{3+14}{7} = \frac{17}{7}$

$3) 7\frac{1}{2} + \frac{1}{2} = \frac{7.2+1}{2} + \frac{1}{2} = \frac{15}{2} + \frac{1}{2} = \frac{15+1}{2} = \frac{16}{2} = \frac{8}{1} = 8$

$4) \frac{6}{7} - \frac{3}{7} = \frac{6-3}{7} = \frac{3}{7}$

$5) \frac{231}{15} - \frac{651}{3} = \frac{15:15.231-15:3.651}{15} = \frac{231-3255}{15} = \frac{-3024}{15} = \frac{-1008}{5}$

$6) 756 \frac{3}{4} - 245 \frac{1}{2} = \frac{756.4+3}{4} - \frac{245.2+1}{2} = \frac{3027}{4} - \frac{491}{2} = \frac{4:4.3027-4:2.491}{4} =$
$\frac{3027-982}{4} = \frac{2045}{4}$