Question

ayuda con la formula general

x2-2x+3=0

x2+6x+9=0

Answer 1

RESOLUCIÓN :

$ax^2+bx+c=0 \\ \\ \boxed{\\ \\ \boxed{\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}} }}$


$x^{2} -2x+3=0 a=1,\:b=-2,\:c=3: \quad x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \:3}}{2\cdot \:1} x_{1} =1+\sqrt{2}i x_{2}=1-\sqrt{2}i$

$x^{2} +6x+9=0 a=1,\:b=-6,\:c=9: x_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\cdot \:9}}{2\cdot \:1}$
$x_{1.2} =\frac{-\left(-6\right)}{2\cdot \:1}:\quad 3$