Question

Factorizar:

a<(2)+a-ab-b

a(x+1)-b(x+1)+c(x+1)

81x<(2)-(a-x)<(2)

x<(2)-x-72

(a+2)<(2)-(a-3)<(2)


<() = potencias

Answer 1

$a^{2}+a-ab-b$
a(a+1) -b(a+1)
(a+1)(a-b)


a(x+1)-b(x+1)+c(x+1)
(x+1)(a-b+c)


$81x^{2} -(a-x) ^{2}$

$[(9x+(a-x) -9x-(a-x)]$

$[9x+a-x] [9x-a+x]$


$x^{2} - x - 72$
x                    -9
x                    +8

-9x+8x = -x

(x-9)(x+8)



$(a+2)^{2} - (a-3)^{2}$

 [ (a+2)+(a-3)] [(a+2) - (a-3)]

 [ a+2+a-3 ] [ a+2 - a +3 ]

[2a-1] [+5]