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Respuestas

Respuesta dada por: maxzriver
0
Sabiendo que
x^2+y^2+Dx+Ey+F=0
Entonces
D=-2h
E=-2k
F=h^2+k^2-r^2

1)D=-6=-2h...................h=3
   E=-2=-2k...................k=1
   F=h^2+k^2-r^2=3^2+1^2-r^2=9+1-r^2=10 -r^2=9......r^2=1.......r=1
(x-3)^2  + (y-1)^2 =1

2)D=0=-2h...................h=0
   E=-8=-2k...................k=4
   F=h^2+k^2-r^2=0^2+4^2-r^2=0+16-r^2=16 -r^2=-33......r^2=49.......r=V49
(x)^2  + (y-4)^2 =49

3)D=10=-2h.................h=-5
   E=0=-2k.....................k=0
   F=h^2+k^2-r^2=(-5)^2+0^2-r^2=25+0-r^2=25 -r^2=21......r^2=4.......r=2
(x+5)^2  + (y)^2 =4

4)D=0=-2h...................h=0
   E=0=-2k...................k=0
   F=h^2+k^2-r^2=0^2+0^2-r^2=0+0-r^2=0 -r^2=-9......r^2=9.......r=3
(x)^2  + (y)^2 =9

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