hallar el lagoritmo de:
 
log(2x+4)-log(x-1)=1

Respuestas

Respuesta dada por: beakman
1
log(2x+4)-log(x-1)=1
log [(2x+4)/log(x-1)] = log 10
(2x+4)/(x-1) = 10
2x + 4 = 10 (x-1)
2x -10x = -10 -4
-8x = -14
 x = -14 / -8
x = 7 / 4

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