Question

Si a=−1/2 y b=−3, entonces el valor numérico de 2b^−1+3a^2, es

Answer 1

$a=- \frac{1}{2} \\ \\ b=-3 \\ \\ \\ 2b^{-1}+3a^2= \\ \\ 2(-3)^{-1}+3( -\frac{1}{2} )^2= \\ \\ 2( \frac{1}{-3} )+3( \frac{1}{4})= \\ \\ - \frac{2}{3} + \frac{3}{4} = \\ \\ \frac{-8+9}{12} = \\ \\ \boxed{\frac{1}{12} } \\ \\ El \ valor \ numerico \ es \ \boxed{ \frac{1}{12}}$