Question

(z+1)(z-3)-(z+2)(z+4)=3z-[4z-2(z-1)]

Answer 1

(z+1)(z-3)-(z+2)(z+4)=3z-[4z-2(z-1)]
z²+3z+z+3-z²+4z+2z+8=3z-(4z-2z+2)
z²+4z+3-z²+6z+8=3z-(2z-2)
10z+11=3z-2z-2
10z+11=z-2
10z-z=-2-11
9z=-13
z= -13/9
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