Question

x(x+1)(x+2)-(x+1)(x-2)(x+3)=x²-1

 

Answer 1

x(x+1)(x+2)-(x+1)(x-2)(x+3)=x²-1
x²+x(x+2)-(x²-x-2)(x+3)=x²-1
x³+2x²+x²+2x-(x³+3x²-x²-3x-2x-6)=x²-1
x³+3x²+2x-x³-3x²+x²+5x+6=x²-1
x²+7x+6=x²-1
x²-x²+7x+6+1=0
7x+7=0
7x=-7
x=-7/7
x=-1