Question

log(16-x^2)/ log (3x-4)= log 2

Answer 1

Log(16-x^2)/ log (3x-4)= log 2
log(16-x²-3x+4)=log=log2
log(-x²-3x+20)=log2
-x²-3x+20=2
0=x²+3x-18
0=(x+6)(x-3)
x+6=0   ∨   x-3=0
    x=-6          x=3