Question

A Δ B = 3A - AB;calcular: [( - 2) Δ ( - 5)] Δ [( - 1) Δ (+3)]

Answer 1

* [(-2) ∆ (-5)] = 3(-2) - (-2)(-5)= (-6)-(10) =-16
*[(-1)∆(+3)]= 3(-1)-(-1)(+3) = (-3)-(-3)= (-3)+3= 0
*[-16∆0]= 3(-16)-(-16)(0)= (-48)-(0) = -48