Question

$\frac{sec x}{tanx + cot x} =senx$

Answer 1

${\frac{secx}{tanx+ctgx}=}\\\\{ \frac{\frac{1}{cosx}}{\frac{senx}{cosx}+\frac{cosx}{senx}} =}\\\\{ \frac{\frac{1}{cosx}}{\frac{sen^2x+cos^2x}{senx.cosx}} =}\\\\{ \frac{\frac{1}{cosx}}{\frac{1}{senx.cosx}} =}\\\\{ \frac{1}{cosx} \times \frac{senx.cosx}{1} =}\\\\{ \frac{senx}{1} =}\\\\{\boxed{senx}}\\\\{\mathbf{salu2.!!\ :)}}\\{\mathbf{Wellington}}$