Question

(6m⁴₋4m³n²₋3m²n⁴₊4mn⁶₋n⁸) entre (2m²-n⁴)

Answer 1

$\frac{6m^4-4m^3n^2-3m^2n^4+4mn^6-n^8}{\left(\sqrt{2}m+n^2\right)\left(\sqrt{2}m-n^2\right)}$