Respuestas
Respuesta dada por:
4
cloruro de bario
BaCl2
calcular masa molecular
Ba: 1 x 137.33 = 137.33 g/mol
Cl: 2 x 35.45 = 70.9 g/mol
``````````````````````````````````````````
Mm = 208.23
2. Calcular %
Bario
208.23 g ------- 100 %
137.33 g ------- x
x = 65.95 % Ba
Cloro
208.23 g ----- 100 %
70.9 g ----- x
x = 34.05 % Cl
````````````````````````````````````````
nitrato de potasio
KNO3
K: 1 x 39.09 = 39.09 g/mol
N: 1 x 14 = 14 g/mol
O = 3 x 16 = 48 g/mol
````````````````````````````````````
Mm = 101.09 g/mol
calcular %
K
101.09 g ------ 100 %
39.09 g ------ x
x = 38.67 % K
Nitrógeno
101.09 g ---- 100 %
14 g ---- x
x = 13.85 % N
Oxigeno
101.09 g ----- 100 %
48 g ----- x
x = 47.48 % O
BaCl2
calcular masa molecular
Ba: 1 x 137.33 = 137.33 g/mol
Cl: 2 x 35.45 = 70.9 g/mol
``````````````````````````````````````````
Mm = 208.23
2. Calcular %
Bario
208.23 g ------- 100 %
137.33 g ------- x
x = 65.95 % Ba
Cloro
208.23 g ----- 100 %
70.9 g ----- x
x = 34.05 % Cl
````````````````````````````````````````
nitrato de potasio
KNO3
K: 1 x 39.09 = 39.09 g/mol
N: 1 x 14 = 14 g/mol
O = 3 x 16 = 48 g/mol
````````````````````````````````````
Mm = 101.09 g/mol
calcular %
K
101.09 g ------ 100 %
39.09 g ------ x
x = 38.67 % K
Nitrógeno
101.09 g ---- 100 %
14 g ---- x
x = 13.85 % N
Oxigeno
101.09 g ----- 100 %
48 g ----- x
x = 47.48 % O
Preguntas similares
hace 6 años
hace 6 años
hace 9 años
hace 9 años
hace 9 años
hace 9 años