Question

calculr :(tgx+1)cosx-cosx

Answer 1

${(tanx+1)cosx-cosx=}\\\\{cosx[(tanx+1)-1]=}\\\\{cosx(tanx+1-1)=}\\\\{cosx(tanx)=}\\\\{cosx\left(\frac{senx}{cosx}\right)=}\\\\{\boxed{senx}}\\\\{\mathbf{salu2.\ :)}}\\{\mathbf{Wellington}}$