Question

f(x) = x^3 + 2x^2 -8 x-1 >> Hallar f(-3)

Answer 1

si F(x)= x^3+2x^2-8x-1. hallar f(-3)

f(-3)=(-3)^3+2(-3)^2-8(-3)-1

f(-3)=-27+2(-9)+24-1

f(-3)=-27-18+24-1

f(-3)=-45+23

f(-3)=-22

f es igual a -22 cuando F tiende a -3