Question

Tg^2x-sen^x=Tg^2x * sen^x

Answer 1

${\tan^2x - \sin^2x=}\\\\{ \frac{\sin^2x}{\cos^2x} - \sin^2x=}\\\\{ \frac{\sin^2x-\sin^2x.\cos^2x}{\cos^2x} =}\\\\{ \frac{\sin^2x(1-\cos^2x)}{cos^2x} =}\\\\{ \frac{\sin^2x(\sin^2x)}{\cos^2x} =}\\\\{ \frac{\sin^2x}{\cos^2x} \times \frac{\sin^2x}{1} =}\\\\{\tan^2x \times \sin^2x}\\\\{\mathbf{salu2.!!\ :)}}\\{\mathbf{Wellington}}$