Question

1+senx+cos^2x/1+senx
respuesta: 2-senx

Answer 1

$\frac{1+senx+cos^2x}{1+senx} =}\\\\{ \frac{1+senx+1-sen^2x}{1+senx} =}\\\\{ \frac{2+senx-sen^2x}{1+senx} =}\\\\{ \frac{-(-2-senx+sen^2x)}{1+senx} =}\\\\{ \frac{-(sen^2x-senx-2)}{1+senx} =}\\\\{ \frac{-(senx-2)(senx+1)}{senx+1} =}\\\\{\text{simplifico el: senx+1}}\\\\{-(senx-2)=}\\\\{-senx +2=}\\\\{\boxed{2-senx} \to \text{comprobada}}\\\\{\mathbf{salu2.!!\ :)}}\\{\mathbf{Wellington}}$