Question

Calcular la raiz de
x²+12x-169=0

Answer 1

x²+12x-169=0

Utilizare formula general:

$x= \frac{-b \frac{+}{} \sqrt{ b^{2} -4ac} }{2a} \\ \\ a=1 \\ b=12 \\ c=-169 \\ \\ Resolvemos: \\ \\ x= \frac{-12 \frac{+}{} \sqrt{ (12)^{2} -4(1)(-169)} }{2(1)} \\ \\ x= \frac{-12 \frac{+}{} \sqrt{ 144+676} }{2} \\ \\ x= \frac{-12 \frac{+}{} \sqrt{ 820} }{2} \\ \\ x= \frac{-12 \frac{+}{}2 \sqrt{ 205} }{2} \\ \\ x= \frac{2(-6 \frac{+}{}1 \sqrt{ 205}) }{2}= \frac{-6 \frac{+}{} \sqrt{ 205} }{1} \\ \\ \boxed{ x1=-6+ \sqrt{205} } \\ \\ \boxed{ x2=-6- \sqrt{205} }$



Suerte''¡¡
Salu2''¡¡
>:D