Respuestas
Respuesta dada por:
19
Ley
de los gases ideales: V · P = n · R · T
V = 10 L
P = atm.
T = 27 ºC + 273 = 300 K
n = 2 moles
R = 0.0821 (L atm / mol K)
P = 2 moles · 0.0821 (L atm/mol K) · 300 K
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10 L
P = 4.926 atm
V = 10 L
P = atm.
T = 27 ºC + 273 = 300 K
n = 2 moles
R = 0.0821 (L atm / mol K)
P = 2 moles · 0.0821 (L atm/mol K) · 300 K
````````````````````````````````````````````````````````
10 L
P = 4.926 atm
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