Question

(tanx+2) (2tanx+1)=5tanx+2sec a la dosx   ... urgente por favor gracias

Answer 1

$(tanx+2)(2tanx+1)=}\\\\{2tan^2x+5tanx+2=}\\\\{ \frac{2sen^2x}{cos^2x} +\frac{5senx}{cosx}+2=}\\\\{ \frac{2sen^2x+5senxcosx+2cos^2x}{cos^2x} =}\\\\{ \frac{2senx^2+2cos^2x+5senxcosx}{cos^2x} =}\\\\{ \frac{2+5senxcosx}{cos^2x} =}\\\\{ \frac{2}{cos^2x} + \frac{5senxcosx}{cos^2x}=}\\\\{2sec^2x+ \frac{5senx}{cosx} =}\\\\{2sec^2x+5tanx}\\\\{salu2.!! :)}$