Question

• El peso molecular de un compuesto es 99,0 g. si su composición centesimal es C=24,3 % H= 4,1% y Cl= 71,6% calcule la formula empírica y la formula molecular del compuesto

Answer 1

C: 24.3 g / 12 g/mol = 2.02 mol
H: 4.1 g / 1 g/mol = 4.1 mol
Cl: 71.6 g / 35.45 g/mol = 2.02 mol

dividir entre el menor de ellos

C: 2.02 mol / 2.02 mol = 1
H: 4.1 mol / 2.02 mol = 2
Cl: 2.02 mol / 2.02 mol = 1

FE: CH2Cl
Mm FE

C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
Cl: 1 x 35.45 = 35.45 g/mol
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         Mm = 49.45 g/mol

n = 99 g/mol
     ``````````````
       49.45 g/mol

n = 2

FM: (CH2Cl)2 = C2H4Cl2 (1,2-dicloroetano)