Question

3(x-1)/4-2(x+3)/3=3-x/6

Answer 1

Resolviendo :

$\dfrac{3(x-1)}{4} - \dfrac{2(x+3)}{3} = 3 - \dfrac{x}{6} \\ \\ \textit{Amplificamos la fracci\'on x3 y x4.} \\ \\ \dfrac{3*3(x-1)}{4*3} - \dfrac{4*2(x+3)}{4*3} = \dfrac{18-x}{6} \\ \\ \dfrac{9(x-1)}{12} - \dfrac{8(x+3)}{12} =\dfrac{18-x}{6}\\ \\ \textit{Fracciones homog\'eneas.} \\ \\ \dfrac{9x-9- 8x - 24}{12} =\dfrac{18-x}{6} \\ \\ \dfrac{x-33}{\not{12}_{2}}} = \dfrac{18-x}{\not{6}_{1}} \\ \\ x - 33 = 39 - 2x \\ \\ x + 2x = 39 + 33 \\ \\ 3x = 72 \\ \\ x=\dfrac{72}{3} \\ \\ \boxed{x=24}$