Question

que volumen ocupara 1.216g de SO2 gaseoso (M=64.1kg/kmol)a 18.0 °C y 775 mmHg, si este actua como un gas ideal

Answer 1

V P = n R T LEY DE LOS GASES IDEALES

R = 0.0821 ( L atm/mol K)
T = 18 ºC + 273 = 291 K
P = 775 / 760 = 1.019 atm
n = masa/ Mm
n = 1.216 g/ 64.1 g/mol
n = 0.0189 mol

V = 0.0189 mol x 0.0821 (L atm / mo K) x 291 K
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                             1.019 atm

V = 0.443 L