Question

1- $(1/4)^{1/3} = (2000)^{1/3}=?$
2- $\sqrt{64}=?$
3- $3\sqrt{16} =?$
4-$\sqrt{81} =?$
5-$\sqrt{400} =?$
6-$\frac{\sqrt{2} * \sqrt{10} }{ \sqrt{5} } =?$
7-$3\sqrt{16} / 3\sqrt{2} =?$
8-$(\frac{2 ^{6} * 3^{12} }{5 ^{20} } ) ^{1/5} =?$

ayudenme porfavor ?

Answer 1

2) $\sqrt{64$ = 8.
3) 3 x $\sqrt{16$ = 3 x 4 = 12.
4) $\sqrt{81$ = $9^2$ = 9.
5) $\sqrt{400$ = $20^2$ = 20.
6) $\sqrt{2$ x $\sqrt{10$ /$\sqrt{5$ =

$\sqrt{2^2 x \sqrt{10$/5 = $\sqrt{2^2 x 10$/5 = $\sqrt{4 x 10$ /$\sqrt{5$ = $\sqrt[4]{40} x \sqrt[4]{5^2} /5$ = $\sqrt[4]{40}x 5^2$/ 5 = $\sqrt[4]{40} x 25$/ 5 = $4 \sqrt{1000$ / 5
7) 3 x $\sqrt{16$/3 x $\sqrt{2$ = 4$\sqrt{2$.
8) ($2^6 x 3^1^2 / 5^2^0$) ^1/5 = 
$(6^6 x 3^6)/ 5^2^0)^1/^5$

(6 x 3)^6/ (5^20) ^1/5 = $\sqrt[5]{18}^6 / 5^2^0$ = $\sqrt[5]{18^6} / 5^4 = <strong>18 \sqrt[5]{18} /625$.