Question

2x + 3y + 1z = 4
-2 x + y + z = 0
-3 x + y - 2z = -3

Sacar los determinantes de x y z

Answer 1

$\left[\begin{array}{ccc}2&3&1\\-2&1&1\\-3&1&-2\end{array}\right] = 2\left[\begin{array}{ccc}1&1\\1&-2\end{array}\right] -3\left[\begin{array}{ccc}-2&1\\-3&-2\end{array}\right]+1\left[\begin{array}{ccc}-2&1\\-3&1\end{array}\right]$


= 2 (- 2 - 1) - 3 (4- ( - 3 ) ) + 1 (-2 - (-3)) 

=2(-3) - 3(4 + 3) + 1(-2+3)

=-6 - 3 (7) + 1(1)

= 6 - 21 + 1

= -14

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