Question

Necesito que me colaboren con la 6 ,7,8

Answer 1

6.
C: 15.5 g/ 12 g/mol = 1.292 mol
Cl: 23 g/ 35.45 g/mol = 0.648 mol
F: 61.5 g / 18.99 = 3.238 mol
divdir entrte el menor de ellos
C: 1.292 mol = 0.648 mol = 2
Cl: 0.648 mol / 0.648 mol = 1
F: 3.238 mol / 0.648 mol = 5

FE: C2HF5

7.
C: 82.7 g/ 12 g/mol = 6.892 mol
H: 17.3 g / 1 g/mol = 17.3 g/mol

dividir entre el menor de ellos

C: 6.892 mol / 6.892 mol = 1  x = 2
H: 17.3 mol / 6.892 mol = 2.5  x 2 = 5

multiplicar por 2 ya que uno de los resultados es 0,5

FE: C2H5

d = m/v            P V  = n R T          n = m/Mm  sustituir

P V = m/Mm R T    despejar    m  = P V
                                                   ````    ``````
                                                  Mm    R T
m = P Mm
````  ````````
 v     R T

d = P  Mm /R T    despejar Mm

Mm = d R T / P

Mm = 2.33 g/L  x  0.0821 (atm L/mol K) x 300 K
         ````````````````````````````````````````````````````````````
                                     098 atm

Mm = 58.55 g/mol del compuesto

Mm de la FE
C: 2 x 12 = 24 g/mol
H: 5 x 1  =  5 g/mol
````````````````````````````
         Mm = 29 g/mol

calcula n = 58.55 g/mol / 29 g/mol

n = 2

FM: (C2H5)2 = C2H10

8.
M = mol soluto / V(L)

V = 750 / 1000 = 0.750 L

M = 0.145 mol / 0.750 L

M = 0.193 molar