Question

Calculate the grams of solute needed to prepare each of the following 2.00l of a 1.50 m naoh solution !

Answer 1

m = mol soluto / Kg svte.

m = 2.00 L = 2.00 Kg svte

1.  Mm NaOH = 40 g/mol

2.  calcular mol

mol = m x Kg svte

mol = 1.50 mol /Kg svte  x  2.00 Kg

mol =3 de NaOH

3. Calcular masa

mol = masa/Mm

masa = mol x Mm

masa = 3 mol x 40 g/mol

masa = 120 g de NaOH