Question

¿me ayudan?, gracias.

[tex] \frac{5}{6} entre \frac{2}{3} =



[tex]1 \frac{8}{27} entre 1 \frac{1}{9} =




[tex](5 \frac{1}{4} -4) entre 1 \frac{1}{2} =




[tex] \frac{5}{6} entre( \frac{2}{3} x \frac{6}{5}) =




[tex] (2\frac{1}{3} + 3 \frac{1}{3} -3 \frac{1}{8}) entre \frac{1}{12} =

Answer 1

$\frac{ \frac{5}{6} }{ \frac{2}{3} } = \frac{5 x 3}{6 x 2} = \frac{15}{12} = \frac{5}{4}$

$\frac{ \frac{8}{27} }{ \frac{10}{9} } = \frac{8x9}{10x27} = \frac{72}{270} = \frac{4}{15}$

$\frac{( \frac{21}{4} -4)}{ \frac{3}{2}}= \frac{ \frac{21-16}{4} }{ \frac{3}{2} } = \frac{ \frac{5}{4} }{ \frac{3}{2} } = \frac{5x2}{4x3} = \frac{10}{12} = \frac{5}{6}$

$\frac{ \frac{5}{6} }{( \frac{2}{3} x \frac{6}{5}) } = \frac{ \frac{5}{6} }{ \frac{12}{15} } = \frac{5x15}{12x6} = \frac{75}{72} = \frac{25}{24}$

$\frac{( \frac{7}{3}+ \frac{10}{3} - \frac{25}{8}) }{ \frac{1}{12} } = \frac{ \frac{56+80-75}{24} }{ \frac{1}{12} } = \frac{ \frac{61}{24} }{ \frac{1}{12} } = \frac{61x12}{24x1} = \frac{61}{2}$