Question

Como se calcula la formula empirica del cloruro de zinc? !

Answer 1

Mm ZnCl2
Zn: 1 x  65,38 = 65.38 g /mol
Cl: 2 x 35.45 = 70.9 g/mol
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                 Mm = 136.28 g/mol


calcular % de cada elemento
zinc:
136.28 g -------  100%
  65.38 g -------      x
x = 47.97 % de Zn

cloro
136.28 g -------  100%
   70.9  g -------      x
x = 52.03 % de Cl

2. calcular mol

Zn = 47.97 g/ 65.38 g/mol = 0.734 mol
Cl: 52.03 g/ 35.45 g/mol = 1.468 mol

3. dividir entre el menor de ellos

Zn: 0.734 mol / 0.734 mol = 1
Cl: 1.468 mol / 0.734 mol = 2

4. Fórmula empírica:  ZnCl2