Question

Uso del paréntesis en la aritmetica

Resuelve...


(3+8)-10

(2+3)-(5+4)

3(2-5)+6

-2(4+5)+22

2(3+2-4)-5(-6+3)

-2(4+1)+52

6(8+2-5)-4(-3+7-4)

-52+33-(6+11)-82

3-11-(5-4-7)+9

42÷3-(2)(-5)+10

18÷2+(4+5)-(6+3-2)

Answer 1

(3+8)-10= (11)-10=1

(2+3)-(5+4)=(5)-(9)=-4

3(2-5)+6=3(-3)+6=-9+6=-3

-2(4+5)+22=-2(9)+22=-18+22=4

2(3+2-4)-5(-6+3)=2(1)-5(-3)=2+15=17

-2(4+1)+52=-2(5)+52=-10+52=42

6(8+2-5)-4(-3+7-4)=6(5)-4(0)=30

-52+33-(6+11)-82=-19-(17)-82=-118

3-11-(5-4-7)+9=-8-(-6)+9=-8+6+9=7

42/3-(2)(-5)+10=14-(-10)=14+10=24

18/2+(4+5)-(6+3-2)=9+(9)-(7)=11



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