Question

hallar x en log(x²2+3x+12) =2

Answer 1

$log(x^2+3x+12) =2 \\x^2+3x+12=10^2 \\x^2+3x+12=100 \\x^2+3x+12-100=0 \\x^2+3x-88=0 \\(x+11)(x-8)=0 \\ \\(x+11)= 0 \ \ \ \ \ \ (x-8)=0 \\x = -11 \ \ \ \ \ \ \ \ \ \ \ \ \ x = 8$