Question

Ayuda para resolver estas fracciones

Answer 1

1) $\frac{2}{3} = \frac{6}{9} = \frac{10}{15} = \frac{18}{27} = \frac{24}{36} = \frac{44}{66}$

$\frac{1}{4} = \frac{3}{12} = \frac{7}{28} = \frac{10}{40} = \frac{12}{48} = \frac{25}{100}$

2)  $\frac{3}{4} + \frac{5}{8} + \frac{1}{2} = \frac{6}{8} + \frac{5}{8} + \frac{4}{8} = \frac{15}{8} = 1 \frac{7}{8}$


$\frac{4}{9} + \frac{2}{3} + \frac{7}{18} = \frac{8 + 12 + 7}{18} = \frac{27}{18} = 1 \frac{9}{18}$

$\frac{3}{14} + \frac{15}{42} + \frac{2}{7} = \frac{9 + 15 + 12}{42} = \frac{36}{12} = 3$