Question

determinar: C= (sen 60 csc 45) + (sen 53 ctg 60)

Answer 1

c=sen (60)csc(45)+sen (53)ctg (60)
c=sen (60)csc(45)+sen(53)×cos (60)/sen (60)
c=sen(60)csc (45)+sen(53)cos(60)/sen (60)
c=0.87889

Answer 2

$Identidades: \\ \\ csc \beta = \frac{1}{sen \beta } \\ \\ cot \beta = \frac{1}{tan \beta } = \frac{cos \beta }{sen \beta }$

Aclarados conceptos resolvemos:

$C=(Sen(60)* \frac{1}{sen(45)} )+(Sen(53)* \frac{cos(60)}{sen(60)} ) \\ \\ C=1,686$

El valor de C=1,686


Suerte''¡¡
Salu2''¡¡